PLEASE REFER TO THE ATTACHED SCREENSHOT FOR THE ACTUAL QUESTION.
11. Consider solution of carbon disulphide with dimethoxymethane at 35.2 ºC. Vapor pressure (in torr) for carbon disulphide, referred to as component 1, is given as
P1=514.5⋅x1 (1.4967×2^2−0.68175×2^3). For pure dimethoxymethane, referred to as component 2, P2 =587.7 torr.
a) Determine partial pressure of dimethoxymethane, P2 (in torr) above the solution for x2=0.25.
b) For solution of carbon disulphide with dimethoxymethane at 35.2 ºC, determine Henry’s law constant (in torr) for carbon disulphide, K1
c) For solution of carbon disulphide with dimethoxymethane at 35.2 ºC, determine Henry’s law constant (in torr) for dimethoxymethane, K2
